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copied!<h2>Simple ways:</h2> <pre><code>var arr = [1,2,,3,,-3,null,,0,,undefined,4,,4,,5,,6,,,,]; arr.filter(n => n) // [1, 2, 3, -3, 4, 4, 5, 6] arr.filter(Number) // [1, 2, 3, -3, 4, 4, 5, 6] arr.filter(Boolean) // [1, 2, 3, -3, 4, 4, 5, 6] </code></pre> <p><strong>or - (only for <em>single</em> array items of type "text")</strong></p> <pre><code>['','1','2',3,,'4',,undefined,,,'5'].join('').split(''); // output: ["1","2","3","4","5"] </code></pre> <p><strong>or - Classic way: simple iteration</strong></p> <pre><code>var arr = [1,2,null, undefined,3,,3,,,0,,,[],,{},,5,,6,,,,], len = arr.length, i; for(i = 0; i < len; i++ ) arr[i] && arr.push(arr[i]); // copy non-empty values to the end of the array arr.splice(0 , len); // cut the array and leave only the non-empty values arr // [1,2,3,3,[],Object{},5,6] </code></pre> <p><br/></p> <h2>via jQuery:</h2> <pre><code>var arr = [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,]; arr = $.grep(arr,function(n){ return n == 0 || n }); arr // [1, 2, 3, 3, 0, 4, 4, 5, 6] </code></pre> <p><br/></p> <h2>UPDATE - just another fast, cool way (using ES6):</h2> <pre><code>var arr = [1,2,null, undefined,3,,3,,,0,,,4,,4,,5,,6,,,,], temp = []; for(let i of arr) i && temp.push(i); // copy each non-empty value to the 'temp' array arr = temp; delete temp; // discard the variable arr // [1, 2, 3, 3, 4, 4, 5, 6] </code></pre> <h3>Remove empty values</h3> <pre><code>['foo', '',,,'',,null, ' ', 3, true, [], [1], {}, undefined, ()=>{}].filter(String) // ["foo", null, " ", 3, true, [1], Object {}, undefined, ()=>{}] </code></pre>

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