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copied!<p>It's relatively simple to write code that will do this. If this is something you're going to be doing a lot however you might want to look into using an existing library like <a href="http://velocity.apache.org/" rel="nofollow noreferrer">Velocity</a>. It uses a different syntax for values however. See <a href="http://velocity.apache.org/engine/devel/webapps.html" rel="nofollow noreferrer">Getting Started</a>.</p> <p>If you do want to write this yourself try:</p> <pre><code>public static String replaceAll(String text, Map<String, String> params) { return replaceAll(text, params, '%', '%'); } public static String replaceAll(String text, Map<String, String> params, char leading, char trailing) { String pattern = ""; if (leading != 0) { pattern += leading; } pattern += "(\\w+)"; if (trailing != 0) { pattern += trailing; } Pattern p = Pattern.compile(pattern); Matcher m = p.matcher(text); boolean result = m.find(); if (result) { StringBuffer sb = new StringBuffer(); do { String replacement = params.get(m.group(1)); if (replacement == null) { replacement = m.group(); } m.appendReplacement(sb, replacement); result = m.find(); } while (result); m.appendTail(sb); return sb.toString(); } return text; } </code></pre> <p>For example:</p> <pre><code>String in = "Hi %FIRST_NAME% %LAST_NAME%."; Map<String, String> params = new HashMap<String, String>(); params.put("FIRST_NAME", "John"); params.put("LAST_NAME", "Smith"); String out = replaceAll(in, params); System.out.println(out); </code></pre> <p>Output:</p> <pre><code>Hi John Smith. </code></pre>

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