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copied!<p>@Jeff</p> <p>I actually think this is an interesting question. I'm not sure how useful it is, but it is a valid question.</p> <p>@Ed</p> <p>Can you provide a little more info on this question? You said the dimension of the array is dynamic, but is the number of elements dynamic as well?</p> <p>EDIT: I'm going to try and answer the question anyways. I can't give you the code off the top of my head (it would take a while to get it right without any compiler here on this PC), but I can point you in the right direction ...</p> <p>Let's use 8 dimensions (0-7) with indexes 0 to 3 as an example. You care about only 1,2 and 6. This means you have two arrays. First, <code>array_care[4][4][4]</code> for 1,2, and 6. The <code>array_care[4][4][4]</code> will hold the end result.</p> <p>Next, we want to iterate in a very specific way. We have the array <code>input[4][4][4][4][4][4][4][4]</code> to parse through, and we care about dimensions 1, 2, and 6.</p> <p>We need to define some temporary indexes:</p> <pre><code>int dim[8] = {0,0,0,0,0,0,0,0}; </code></pre> <p>We also need to store the order in which we want to increase the indexes:</p> <pre><code>int increase_index_order[8] = {7,5,4,3,0,6,2,1}; int i = 0; </code></pre> <p>This order is important for doing what you requested.</p> <p>Define a termination flag:</p> <pre><code>bool terminate=false; </code></pre> <p>Now we can create our loop:</p> <pre><code>while (terminate) { array_care[dim[1]][dim[2]][dim[6]] += input[dim[0]][dim[1]][dim[2]][dim[3]][dim[4]][dim[5]][dim[6]][dim[7]]; while ((dim[increase_index_order[i]] = 3) && (i < 8)) { dim[increase_index_order[i]]=0; i++; } if (i < 8) { dim[increase_index_order[i]]++; i=0; } else { terminate=true; } } </code></pre> <p>That should work for 8 dimensions, caring about 3 dimensions. It would take a bit more time to make it dynamic, and I don't have the time. Hope this helps. I apologize, but I haven't learned the code markups yet. :(</p>

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