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copied!<p>Yes, it does depend on system specification. One system might be 10 times faster than another, so it will run bubblesort and quicksort on a set of data 10 times faster than the other.</p> <p>But when you do analysis of algorithms, you often ignore constant factors like that, which is one thing that big-O notation does. So bubblesort is O(n^2) and quicksort is O(nlogn) (in the average case), and that holds no matter how fast your hardware is.</p> <p>The interesting thing is when you start comparing apples and oranges. If you're running bubblesort on your fast hardware, you may find it's faster than quicksort on the slow hardware -- but only up to a point. Eventually, with a large enough input set, the quicksort on the slow hardware is going to be faster than bubblesort on the fast hardware.</p> <p>If you want to start making comparisons like that, you need to do two things together: determine algorithmic complexity including the constant factors, and develop a speed model (e.g. how many iterations of a particular loop it can perform per second) for the actual hardware you're running on. One of the interesting things about Knuth's <a href="http://rads.stackoverflow.com/amzn/click/0201485419" rel="nofollow noreferrer">Art of Computer Programming</a>, compared with other books on algorithms, is that he does both, so that for each algorithm he examines, he calculates how many units of execution time it will take for a given size of input on his (mythical) MIX computer. You could then adjust the calculation for faster or slower hardware -- something that big-O notation doesn't help with.</p>

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