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copied!<p>You might want to check into something like Linq-to-XML:</p> <pre><code>XDocument coordinates = XDocument.Load("yourfilename.xml"); foreach(var coordinate in coordinates.Descendants("coordinate")) { string time = coordinate.Attribute("time").Value; string initial = coordinate.Element("initial").Value; string final = coordinate.Element("final").Value; // do whatever you want to do with those items of information now } </code></pre> <p>That should be a lot easier than using straight low-level XmlTextReader....</p> <p>See <a href="http://www.switchonthecode.com/tutorials/introduction-to-linq-simple-xml-parsing" rel="noreferrer">here</a> or <a href="http://colinmackay.co.uk/blog/2008/04/08/introduction-to-linq-to-xml/" rel="noreferrer">here</a> (or a great many other places) for introductions to Linq-to-XML.</p> <hr> <p><strong>UPDATE:</strong> </p> <p>please try this code - if it works, and you get all the coordinates in that resulting list, then the Linq-to-XML code is fine:</p> <p>Define a new helper class:</p> <pre><code>public class Coordinate { public string Time { get; set; } public string Initial { get; set; } public string Final { get; set; } } </code></pre> <p>and in your main code:</p> <pre><code>XDocument xdoc = XDocument.Load("C:\\test.xml"); IEnumerable<XElement> cords= xdoc.Descendants("coordinate"); var coordinates = cords .Select(x => new Coordinate() { Time = x.Attribute("time").Value, Initial = x.Attribute("initial").Value, Final = x.Attribute("final").Value }); </code></pre> <p>How does this list and its contents look like?? Do you get all the coordinates you're expecting??</p>

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