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copied!<p>Changing the code to yield <code>n</code> chunks rather than chunks of <code>n</code>:</p> <pre><code>def chunks(l, n): """ Yield n successive chunks from l. """ newn = int(len(l) / n) for i in xrange(0, n-1): yield l[i*newn:i*newn+newn] yield l[n*newn-newn:] l = range(56) three_chunks = chunks (l, 3) print three_chunks.next() print three_chunks.next() print three_chunks.next() </code></pre> <p>which gives:</p> <pre><code>[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17] [18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35] [36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55] </code></pre> <p>This will assign the extra elements to the final group which is not perfect but well within your specification of "roughly N equal parts" :-) By that, I mean 56 elements would be better as (19,19,18) whereas this gives (18,18,20).</p> <p>You can get the more balanced output with the following code:</p> <pre><code>#!/usr/bin/python def chunks(l, n): """ Yield n successive chunks from l. """ newn = int(1.0 * len(l) / n + 0.5) for i in xrange(0, n-1): yield l[i*newn:i*newn+newn] yield l[n*newn-newn:] l = range(56) three_chunks = chunks (l, 3) print three_chunks.next() print three_chunks.next() print three_chunks.next() </code></pre> <p>which outputs:</p> <pre><code>[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18] [19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37] [38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55] </code></pre>

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