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POConvert list into sub-list while maintaining "key"
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  1. POConvert list into sub-list while maintaining "key"
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    copied!<p>I have a list that contains a 'key' and 'paragraph'. Each 'key' is associated with a 'paragraph'.</p> <p>My goal is to break each paragraph into individual sentences, with each sentence being assign to the 'key' they originally belonged to in paragraph form. For example:</p> <pre><code>(['2925729', 'Patrick came outside and greeted us promptly.'], ['2925729', 'Patrick did not shake our hands nor ask our names. He greeted us promptly and politely, but it seemed routine.'], ['2925728', 'Patrick sucks. He farted politely, but it seemed routine.']) </code></pre> <p>Right now I've been able to write code to break out sentences into paragraphs, and get the number of hits for each sentence against a dictionary. I now want to associate an ID to each question.</p> <p>Here is the code that deals with sentences without any 'key'. Step1 and 2 I omitted for space conservation: </p> <pre><code>Dictionary = ['book', 'should have', 'open'] ####Step3##### #Create Blank list to append final output final_out = [] ##Find Matches for sent in sentences: for sent in sentences: final_out.append((sent, sum(sent.count(col) for col in dictionary))) #####Spit out final distinct output ##Output in dictionary structure final_out = dict(sorted(set(final_out))) ####Get sentences and rank by max first import operator sorted_final_out = sorted(final_out.iteritems(),key = operator.itemgetter(1), reverse = True) </code></pre> <p>The output from this is: <strong><em>(['johny ate the antelope', 80], ['sally has a friend',20])</em></strong> and so on. I then pick the top X b magnitude. What I am now trying to achieve is something like this: <strong>(['12222','johny ate the antelope', 80], [22332,'sally has a friend',20])</strong>. So i basically want to ensure that all sentences when parsed out are assigned to a 'key'. This is complicated sorry. Again that is why John's earlier solution would work on a simpler case.</p>
 

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