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copied!<blockquote> <p>I am wondering why this line of code is only printing the first character <code>H</code> of a literal character array <code>string</code> and not the full string <code>"Hello"</code> </p> </blockquote> <pre><code>char *myCharPointer = "Hello"; </code></pre> <p><code>myCharPointer</code> is pointer to the first character of the string literal <code>Hello</code>, i.e, <code>H</code>. Buy using <code>*</code> operator in <code>*myCharPointer</code> you are dereferencing the pointer <code>myCharPointer</code> which will give the value stored at the location pointed by <code>myCharPointer</code> which is <code>H</code>. That's why you are getting <code>H</code>. </p> <blockquote> <p>I also tried changing the format specifier to %s, but the program crashed. </p> </blockquote> <p><code>*myCharPointer</code> is of <code>char</code> type and you need <code>%c</code> specifier to print a <code>char</code>. To print the string literal use <code>%s</code> specifier </p> <pre><code> printf("The value of myCharPointer is %s \n \n", myCharPointer); </code></pre> <p>To print the value of the address use <code>%p</code> specifier </p> <pre><code> printf("The value of myCharPointer is %p \n \n", (void *)myCharPointer); </code></pre> <p>The snippet </p> <pre><code>int myIntArray[10]; int *myIntArrayPointer; myIntArrayPointer = myIntArray; </code></pre> <p>is valid because <code>myIntArrayPointer</code> is <code>pointer to int</code> type. Array name are decays to pointer (not always) and hence <code>myIntArray</code> is also a pointer to int type and that's why <code>myIntArrayPointer = myIntArray;</code> is valid. </p> <pre><code>int myIntArray[10]; int *myIntArrayPointer; myIntArrayPointer = &myIntArray; </code></pre> <p><code>&myIntArray</code> is of type <code>int (*)[10]</code> i.e, pointer to array of 10 integers. As I stated above <code>myIntArrayPointer</code> is of type <code>int *</code> and hence assignment is not valid . </p> <blockquote> <p>I also tried changing the format specifier to %s, but the program crashed. </p> </blockquote>

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