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POCannot require a file in Symfony from google-api-php-client
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  1. POCannot require a file in Symfony from google-api-php-client
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    copied!<p>I need to use google-api-php-client.To do so, I added Google's github repository to my composer.json</p> <pre><code>"repositories": [ { "type": "package", "package": { "name": "google/google-api-php-client", "version": "dev-master", "source": { "type": "git", "url": "https://github.com/google/google-api-php-client.git", "reference": "master" }, "autoload" :{ "classmap": ["src"] } } } ] </code></pre> <p>...</p> <pre><code>"require" : { ... "google/google-api-php-client": "dev-master" } </code></pre> <p>Everything is installed properly and I have the following directory structure:</p> <pre><code>/vendor /google /google-api-php-client /examples /src /Google Client.php </code></pre> <p>When I create an object in my Controller, doing the following :</p> <pre><code>$client = new \Google_Client(); </code></pre> <p>The path and the class are found. However, I get the following error :</p> <pre><code>ContextErrorException: Warning: require_once(Google/Auth/AssertionCredentials.php): failed to open stream: No such file or directory in /Users/etienne/Developpement/Ima-Tech/Clients/lesoptions/vendor/google/google-api-php-client/src/Google/Client.php line 18 </code></pre> <p>In my Client.php file, I have the following at the beginning of the file:</p> <pre><code>require_once 'Google/Auth/AssertionCredentials.php'; </code></pre> <p>If I change the line to :</p> <pre><code>require_once 'Auth/AssertionCredentials.php'; </code></pre> <p>everything works fine for that inclusion. However, I don't want to change each <code>require_once</code> in every file of the google-api-php-client project. I'm sure there is a way to change the inclusion path or something therefore I'm wondering how can I tell that the namespace "Google" is the current directory ? </p> <p><strong>Edit 1 :</strong> I'm guessing that this may be caused because this project (google-api-php-client) does not use namespaces...</p>
 

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