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POJoining 8 strings to form 1 string in C
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  1. POJoining 8 strings to form 1 string in C
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    copied!<p>I am doing a <code>C</code> programming school project. In one part of the project, I need to join every 8 strings (each 4 characters in length) to form 1 string (each 32 characters in length). </p> <p>For example, <code>char *holdBinary[16]</code> holds 16 strings such as:</p> <pre><code>holdBinary[0] = "0000"; holdBinary[1] = "0000"; holdBinary[2] = "0000"; holdBinary[3] = "0000"; holdBinary[4] = "0000"; holdBinary[5] = "0000"; holdBinary[6] = "0000"; holdBinary[7] = "0000"; holdBinary[8] = "0000"; holdBinary[9] = "0000"; holdBinary[10] = "0010"; holdBinary[11] = "1010"; holdBinary[12] = "0000"; holdBinary[13] = "0000"; holdBinary[14] = "0000"; holdBinary[15] = "0000"; </code></pre> <p>I need to join every 8 strings in <code>holdBinary</code> to form 1 string which is held in <code>holdRange</code> char array. Thus, the results: <code>holdeRange[0] = "00000000000000000000000000000000"</code> which is formed by <code>holdBinary[0]</code>, <code>holdBinary[1]</code> .... <code>holdBinary[7]</code> and <code>holdeRange[1] = "00000000001010100000000000000000"</code>.</p> <p>Here is the code:</p> <pre><code>char holdRange[2][33]; // I changed here and it works correct now int hold = 0; int z = 0; int index2 = -1; while(z&lt;16) { if(z%8 == 0) { index2++; strcpy(holdRange[index2] , holdBinary[z]); } else { strcat(holdRange[index2] , holdBinary[z]); } z++; } printf("%s" , holdRange[0]); --&gt; prints 0000000000000000000000000000000000000000001010100000000000000000 printf("\n"); printf("%s" , holdRange[1]); --&gt; prints 00000000001010100000000000000000 </code></pre> <p>Thus, <code>holdRange[0]</code> is not equal to what must be. How can I fix it?</p>
 

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