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PORegex returns text of every line with match, when text is inside variable
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  1. PORegex returns text of every line with match, when text is inside variable
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    copied!<p>How can one formulate a regex in Python to return the line where the pattern is found, in a <code>grep</code>-like manner? Say I have the following text (the output of a shell command called with <code>subprocess</code>), assigned to a variable called output:</p> <pre><code>output = "Lorem Ipsum is simply dummy text.\nLorem Ipsum has been the industry's standard\nIt has survived not only five centuries\nIt was popularised in the 1960s with the release of" </code></pre> <p>(sorry about the length, but it's closer to a real example. So the challenge now is to split the string according to <code>\n</code> and then search every line independently. So, we can start with </p> <pre><code>output_lines = re.split(r'\n', output) </code></pre> <p>and get a list, where each element is a line. We now have:</p> <pre><code> &gt;&gt;&gt; print output_lines ['Lorem Ipsum is simply dummy text.', 'Lorem Ipsum has been the industry's standard', 'It has survived not only five centuries', 'It was popularised in the 1960s with the release of'] </code></pre> <p>How would you suggest I search through <code>output_lines</code> for the lines that contain my requested pattern, say "Lorem"?</p> <p>I tried the obvious:</p> <pre><code>for line in output_lines: if re.search(r"Lorem",line): print line </code></pre> <p>And it works. But, does anyone know of a more compact (and possibly elegant) way to get this done?</p>
 

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