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POHow to loop over an array and when we reach the end start over?
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copied!<p>I have an array of urls that I want to do pass to a function, I'll be using a cron job to pass only 2 of them every 10 minutes, I'm storing the last passed index of this array in a database, the problem is I don't know how to pass the first 2 elements when the last passed element is the last one in the array, let me explain with the code:</p> <pre><code>$sites = array( 'http://www.example.com/', 'http://www.example1.com/', 'http://www.example2.com/', 'http://www.example3.com/', 'http://www.example4.com/', 'http://www.example5.com/' ); // the number of urls to pass to the function // Edit: I forgot to say that this number might change later $sites_to_pass = 2; // this value is supposed to be stored when we finish processing the urls $last_passed_index = 2; // this is the next element's index to slice from $start_from = $last_passed_index + 1; // I also want to preserve the keys to keep track of the last passed index $to_pass = array_slice($sites, $start_from, $sites_to_pass, true); </code></pre> <p><code>array_slice()</code> is working fine, but when the <code>$last_passed_index</code> is <code>4</code> I only get the last element in the array, and when it's <code>5</code> (the last index) I get an empty array.</p> <p>What I want to do is when it's <code>4</code> to get the last element and the first element, and when it's <code>5</code> which is the last element's index to get the first 2 elements in the array.</p> <p>I'm not so good with php, any suggestions what should I do instead of creating a function to check the indexes ?</p>

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