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copied!<p>Well, i think you can resolve it in view-side. I dont know your views, but I give an example:</p> <pre><code>def checklist_options(request): # I dont know how you get your query checklist_options = CheckOption.objects.all() #I dont know where it comes from is_master = True if is_master: masters_checklist_options = checklist_options.filter(is_master=True) #I dont know where it comes from is_ingest = True if is_ingest: ingest_checklist_options = checklist_options.filter(is_ingest=True) return render(request, ' main.html', { "masters_checklist_options": masters_checklist_options "ingest_checklist_options": ingest_checklist_options },) </code></pre> <p>So, your main.html can be:</p> <pre><code><div class="ingest"> {% includes "checklist.html" with collection=ingest_checklist_options %} </div> <div class="master"> {% includes "checklist.html" with collection=master_checklist_options %} </div> </code></pre> <p>and checklist.html:</p> <pre><code>{% for option in collection %} do something {% endfor %} </code></pre> <p>What do you win?</p> <p>You let your login in views (it should be in models, maybe).</p> <p>You avoid the n+1 problem when you call <code>{% if option.is_master %}</code>, as an example. Because in each rendering of check_list.html, you already had filterer the <code>is_master</code> or <code>is_ingest</code> options.</p> <p>I hope you undestand my point, i've guessed you models and give you a fool view example. If you need help, show us your view and models, and i'll be able to help you more.</p> <p>Hope helps</p>

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