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copied!<p>That's because a polygon is not a not a Leaflet layer, rather it is <a href="http://leafletjs.com/reference.html#polygon" rel="nofollow">an extension of the Path class</a>. It never inherits the <code>.removeLayer()</code> method from the <a href="http://leafletjs.com/reference.html#layergroup" rel="nofollow">Layer Group class</a>. Instead it can be removed like so:</p> <pre><code>window.map.removeLayer(polygon); </code></pre> <p>Refactoring the code snippet to take this into account we get</p> <pre><code>map.on('zoomend', function(e){ console.log(map.getZoom()); //This is going to be a function that gets dynamically built. var polygons = L.polygon([ [43.22519, -107.69348], [42.99259, -105.48523], [42.26105, -107.7594] ]).bindPopup("Potential Geo polygon area of companies with violations."); if(map.getZoom() >= 5){ map.removeLayer(geojson); }//order matters if(map.getZoom() == 5){ geojson = L.geoJson(statesData, { style: style, onEachFeature: onEachFeature }).addTo(map); } if(map.getZoom() == 7){ if(map.hasLayer(polygons)){ console.log("TEst"); } window.map.removeLayer(polygon); } if(map.getZoom() == 6){ polygons.addTo(map) } }); </code></pre> <p>An alternative approach would be to use <a href="http://geojson.io/#map=2/20.0/0.0" rel="nofollow">geojson.io</a> to create some geoJSON with your polygon latitude, longitude arrays and then add them to the map with the <code>L.geoJson</code> method if you prefer the <code>removeLayer()</code> method.</p> <p>Additionally, you can catch and debug many of these errors via your browsers JavaScript console. Here's an excellent course via <a href="http://discover-devtools.codeschool.com/" rel="nofollow">Code School</a> to help you better use Chrome's console to understand JavaScript errors.</p>

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