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POA more efficient way that takes less space? this is a method btw
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  1. POA more efficient way that takes less space? this is a method btw
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    copied!<p>Here's part of a code for a Rock Paper Scissors project and im just wondering if there is a way to do this that takes up less space. Preferably more efficient too. Basically this is a method and what this method does is compare user inputs to see if one side beats the other. Thanks.</p> <pre><code>public String determineWinner() { String winner = "yolo"; //if fail if(compChoice.equals("S") &amp;&amp; (playChoice.equals("s"))) { winner = "nobody. There was a tie because you guessed the same thing."; } if(compChoice.equals("P") &amp;&amp; (playChoice.equals("p"))) { winner = "nobody. There was a tie because you guessed the same thing."; } if(compChoice.equals("R") &amp;&amp; (playChoice.equals("r"))) { winner = "nobody. There was a tie because you guessed the same thing."; } if(compChoice.equals(playChoice)) //R R, R P, R S { winner = "nobody. There was a tie because you guessed the same thing."; } if(compChoice.equals("R") &amp;&amp; (playChoice.equals("P") || playChoice.equals("p"))) //R P { winner = "player because Paper beats Rock."; } if(compChoice.equals("R") &amp;&amp; (playChoice.equals("S") || playChoice.equals("s"))) //R S { winner = "computer because Rock beats Scissors."; } if(compChoice.equals("P") &amp;&amp; (playChoice.equals("R") || playChoice.equals("r")))//P R { winner = "computer because Paper beats Rock."; } if(compChoice.equals("P") &amp;&amp; (playChoice.equals("S") || playChoice.equals("s")))//P S { winner = "player because Scissors beats Paper."; } if(compChoice.equals("S") &amp;&amp; (playChoice.equals("R") || playChoice.equals("r"))) //S R { winner = "player because Rock beats Scissors."; } if(compChoice.equals("S") &amp;&amp; (playChoice.equals("P") || playChoice.equals("p"))) //S P { winner = "computer because Scissors beats Paper."; } return winner; } </code></pre>
 

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