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copied!<p><code>Out of memory heap space</code> comes into picture is the program is going in an infinite loop.</p> <p>Your code :</p> <pre><code> while (true) { try { lastInput = Input.readLine(); } catch (IOException e) {} if (lastInput != null) { System.out.println(lastInput); if (lastInput.startsWith("Chat: ")) { sendToAllClients(lastInput.substring(7)); } } </code></pre> <p>says that the code inside the loop will run infinite many times without any condition acting as an exit condition. Even when an issue is coming : you are catching that exception and the code keeps on continuing inside the loop.</p> <p>This leads to <code>Out of Memory : Heap Space.</code></p> <p>Suggesed solution :</p> <pre><code>while (true) { try { lastInput = Input.readLine(); } catch (IOException e) { break; } if (lastInput != null) { System.out.println(lastInput); if (lastInput.startsWith("Chat: ")) { sendToAllClients(lastInput.substring(7)); } } } </code></pre> <p>This loop would break as soon user enters any name that causes an exception(which actually acts as an exit condition foe the while loop)</p> <p><strong>EDIT</strong></p> <p>One area which I see could be the source of the issue could be : </p> <pre><code>lastInput.substring(7) </code></pre> <p>If the <code>lastInput</code> string is of huge size that could almost fill up the <code>heap space of the JVM</code> installed on the system, then calling a <code>substring</code> from the <code>7th character to the last character</code>, would internally trigger the creation of new <code>String</code> (as Strings are immutable), & with not enough heap space left, <code>substring</code> execution gives an <code>OutOfMemory exception</code>.</p>

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