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copied!<p>Too understand what is going on you can made little changes to you program. According to the default argument promotions rules from C standard <code>printf()</code> promotes <code>float</code> to <code>double</code>. Thus we can take a look on what is going on with numbers in the operations in <code>double</code> format (more fraction part digits):</p> <pre><code> while (j>=0) { printf ("%3.18lf ", j*0.1); printf ("%3.18lf ", broj); printf ("%3.18lf ", broj - j*0.1); /*printf ("%3.18lf ", (double)(broj-(j*0.1)));*/ break; j--; } </code></pre> <p>The output:</p> <pre><code>9 0.000000000000000000 0.000000000000000000 0.000000000000000000 0. red 0.100000000000000006 0.100000001490116119 0.000000001490116114 1. red 0.200000000000000011 0.200000002980232239 0.000000002980232228 2. red 0.300000000000000044 0.300000011920928955 0.000000011920928938 3. red 0.400000000000000022 0.400000005960464478 0.000000005960464455 4. red 0.500000000000000000 0.500000000000000000 -0.000000000000000028 5. red 0.600000000000000089 0.600000023841857910 0.000000023841857877 6. red 0.700000000000000067 0.699999988079071045 -0.000000011920928994 7. red 0.800000000000000044 0.800000011920928955 0.000000011920928911 8. red 0.900000000000000022 0.899999976158142090 -0.000000023841857960 9. red </code></pre> <p>Output shows <strong>effects caused by finite precision of numbers</strong>. Thus third column is supposed to be consisting of zeros only but it doesn't, because of this effect.</p>

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