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copied!<p>to solve this problem ,you can subtract <code>48</code> from <code>i</code> every time you use value of variable <code>i</code> to assign it to the variables of your algorithm : <code>a</code>,<code>b</code>,<code>c</code>,<code>d</code> , in this case the answer to your example 560316 will be 11 ,and I believe it's the largest sum of 3 consecutive digits, That will work because <code>48</code> is the ascii code of the digit 0 ,49 is for the digit 1 and so on, so your code should be like this :</p> <pre><code> #include <stdio.h> int isempt(int a) { if ((a==' ')||(a=='\n')||(a=='\t')) { return 1; } else return 0; } void main() { int a, b, c, d, e, i, maxsum; a = 0; b = 0; c = 0; d = 0; maxsum = 0; i = 0; int counter = 0; //the variables "numsearch" and "inside" indicate whether program is in the number or outside it int numsearch = 1; int inside = 0; while ((i = getchar())!=EOF) { if (numsearch==1) { if (isempt(i)==0) { numsearch = 0; inside = 1; a = i - '0'; counter++; } } else if ((isempt(i)==0)&&(inside==1)) { if (counter == 1) { b = i - '0' ; counter++; } else if (counter == 2) { c = i - '0'; counter++; } else if (counter == 3) { d = i - '0'; maxsum = a+b+c; if ((b+c+d) > maxsum) { maxsum =( b+c+d); } a =b; b = c; c = d; counter++; } else if (counter == 4) { d = i - '0' ; if ((b+c+d)>maxsum) { maxsum = b+c+d; } a=b; b=c; c=d; } } else if ((counter>=3)&&(isempt(i)==1)) { printf("\n%d\n", maxsum ); counter = 0; numsearch = 1; inside = 0; a = 0; b = 0; c = 0; d = 0; } else { counter = 0; numsearch = 1; inside = 0; a = 0; b = 0; c = 0; d = 0; } } } </code></pre>

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