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copied!<p>I'm new to the network communication and I'm trying to build client-server application.</p> <pre><code>protected void init(){ Server myServer = new Server(); Client myClient = new Client(); } </code></pre> <p>That's my Client class:</p> <pre><code>public class Client { public Client() { init(); } private void init() { Socket echoSocket = null; DataOutputStream os = null; DataInputStream is = null; DataInputStream stdIn = new DataInputStream(System.in); try { echoSocket = new Socket("localhost", 1234); os = new DataOutputStream(echoSocket.getOutputStream()); is = new DataInputStream(echoSocket.getInputStream()); os.writeInt(stdIn.readInt()); echoSocket.getOutputStream().close(); echoSocket.getInputStream().close(); echoSocket.close(); } catch (IOException e) { e.printStackTrace(); } } } </code></pre> <p>And that's server:</p> <pre><code>public class Server { public Server() { init(); } private void init() { try { boolean run = true; ServerSocket ss = new ServerSocket(1234); Socket s = ss.accept(); DataInputStream dis = new DataInputStream(s.getInputStream()); System.out.println(dis.readInt()); s.getInputStream().close(); s.getOutputStream().close(); s.close(); } catch (IOException e) { e.printStackTrace(); } } } </code></pre> <p>First of all: Can I initialize client and server simply like i did? <code>new Server()</code> and <code>new Client()</code>?</p> <p>Question 2: Is it important what i initialize at first? client or server?</p> <p>Question 3: When i compile this code with client first initialized, i become <code>Connection refused: connect</code>. I know it means that there is no listening socket running on the port you are trying to connect to. That's why server must go first, i think. Is it so? can i fix it using <code>setSoTimeout</code> and how?</p> <p>Question 4: When i compile it with server and then client, output is nothing. And i think it has nothing to do with client, because if i try to print "1", for example, it doesn't work either. I think it just waits for the client and does nothing that goes after. How can i fix this? maybe <code>setSoTimeout</code> goes here too?</p>

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