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copied!<p>I have these two scripts, <code>configScript.sh</code>and <code>genScript.sh</code>. The first one works just the way I want it to work. It adds the correct values into <code>options.sh</code> and <code>echo</code> the right message. However, I want <code>genScript.sh</code> to accept the current argument in <code>options.sh</code> and output the correct <code>echo</code>. As it is now when I run <code>genScript.sh</code> it returns <code>null</code> and I can't figure out why.</p> <pre><code>#!/bin/bash -x #configScript.sh func() { echo " Choose 1 - Option 1 2 - Option 2 " echo -n " Enter selection: " read select case $select in 1 ) echo " Option 1 chosen" . ./genScript.sh one cat << EOF >options.sh OPTION=$OPTION EOF ;; 2 ) echo " Option 2 chosen" . ./genScript.sh two cat << EOF >options.sh OPTION=$OPTION EOF ;; esac } func </code></pre> <hr> <pre><code>#!/bin/bash -x #genScript.sh . options.sh OPTION=$1 func2() { if [ "$OPTION" == one ] ; then echo "Option one" elif [ "$OPTION" == two ] ; then echo "Option two" else echo "null" fi } func2 </code></pre> <p>I managed to get <code>genScript.sh</code> to work the way I want by removing <code>OPTION=$1</code>. When I do that <code>genScript.sh</code> will accept the value inside <code>options.sh</code> and will output the right <code>echo</code> . BUT when I remove <code>OPTION=$1</code> <code>configScript.sh</code> stops working as it should, it doesn't update <code>options.sh</code> with a new value anymore.</p>

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