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POReversing byte order in .NET
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  1. POReversing byte order in .NET
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    copied!<p>In the code below, why do X and Y take on different values than what I would think intuitively?</p> <p>If the bytes 0-7 are written to the buffer, shouldn't the resulting long have bytes in the same order? It's like it's reading the long values in reverse order.</p> <pre><code>x 0x0706050403020100 long y 0x0706050403020100 long z 0x0001020304050607 long MemoryStream ms = new MemoryStream(); byte[] buffer = new byte[] { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07 }; ms.Write(buffer, 0, buffer.Length); ms.Flush(); ms.Position = 0; BinaryReader reader = new BinaryReader(ms); long x = reader.ReadInt64(); long y = BitConverter.ToInt64(buffer, 0); long z = BitConverter.ToInt64(buffer.Reverse&lt;byte&gt;().ToArray&lt;byte&gt;(), 0); byte[] xbytes = BitConverter.GetBytes(x); byte[] ybytes = BitConverter.GetBytes(y); byte[] zbytes = BitConverter.GetBytes(z); </code></pre> <p>(I don't know what to tag this question, beyond just .NET.)</p> <hr> <pre><code>BitConverter.IsLittleEndian </code></pre> <p>is false. If my computer is big endian, why does this happen?</p> <ul> <li>This is a Windows 7 64-bit machine</li> <li>Intel Core2 Quad Q9400 2.66&nbsp;GHz LGA 775 95W Quad-Core Processor Model BX80580Q9400</li> <li>SUPERMICRO MBD-C2SBX+-O LGA 775 Intel X48 ATX Intel Motherboard</li> </ul> <p>The results of this code (in response to Jason's comment):</p> <pre><code>byte[] buffer = new byte[] { 0x00, 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07 }; long y = BitConverter.ToInt64(buffer, 1); Console.WriteLine(BitConverter.IsLittleEndian); Console.WriteLine(y); </code></pre> <p>Result:</p> <pre><code>False 506097522914230528 </code></pre>
 

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