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copied!<p>To expand on what Reimeus said: <code>Scanner.next()</code> returns the next <em>token</em> from the scanner. Basically, it regards whitespace as a delimiter between tokens meaning that "Marko Scekic" is two different tokens: "Marko" being the first, and "Scekic" being the second. </p> <p>You may be thinking of it like this: first the code does a System.out.println("What is your name?"); then asks the user for information using <code>next()</code> and then prints something else with <code>System.out.println()</code> so it seems that <code>next()</code> should give everything that was input between the two <code>println()</code> calls. </p> <p>Unfortunately, the Scanner class doesn't know anything at all about whether System.out.println() has been called or not. From its point of view the following are exactly the same: </p> <pre><code>String name; System.out.print("What is yout name?: "); name = user_input.next(); String quest; System.out.print("What is your quest?: "); quest = user_input.next(); </code></pre> <p>and</p> <pre><code>String name; name = user_input.next(); String quest; quest = user_input.next(); </code></pre> <p>In other words, printing things using <code>System.out.println()</code> has no effect on what <code>next()</code> does. </p> <p>So you need to either use something different than <code>Scanner</code>, or as Reimus said, use <code>nextLine()</code>, since this will return everything from the beginning of the line until the point that the user hits the enter key (which is a '\n' character).</p>

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