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copied!<p>As @TJ. Crowder told you, need to understand the ´AND´ (´&&´) operation and ´OR´ (´||´)</p> <p>This is a compiling approach to your solution, but you need to improve the code to get it working. Hope you have a good time learning Java.</p> <pre><code>import java.util.Scanner; public class RockPaperScissorsTest { public static void main(String[] args) throws Exception { Scanner input = new Scanner(System. in ); int P1 = 0; int P2 = 0; do { System.out.println("Player 1, choose 1 for rock, 2 for paper, or 3 for scissors."); P1 = input.nextInt(); } while (P1 != 1 && P1 != 2 && P1 != 3); System.out.println(""); System.out.println(""); System.out.println(""); do { System.out.println("Player 2, choose 1 for rock, 2 for paper, or 3 for scissors."); P2 = input.nextInt(); } while (P2 != 1 && P2 != 2 && P2 != 3); if (P1 == 1 && P2 == 1) System.out.println("It's a tie!"); if (P1 == 1 && P2 == 2) System.out.println("Player 2 wins!"); if (P1 == 1 && P2 == 3) System.out.println("Player 1 wins!"); if (P1 == 2 && P2 == 1) System.out.println("Player 1 wins!"); if (P1 == 2 && P2 == 2) System.out.println("It's a tie!"); if (P1 == 2 && P2 == 3) System.out.println("Player 2 wins!"); if (P1 == 3 && P2 == 1) System.out.println("Player 2 wins!"); if (P1 == 3 && P2 == 2) System.out.println("Player 1 wins"); if (P1 == 3 && P2 == 3) System.out.println("It's a tie!"); } </code></pre> <p>}</p>

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