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copied!<p>Upon further clarification in the comments section:</p> <p>Yes, you can represent your number as a std::string in C++.</p> <p><a href="http://rosettacode.org/wiki/Increment_a_numerical_string#C.2B.2B" rel="nofollow noreferrer">Here</a> you find code for incrementing a number represented as a string:</p> <pre><code>#include <string> #include <iostream> #include <ostream> void increment_numerical_string(std::string& s) { std::string::reverse_iterator iter = s.rbegin(), end = s.rend(); int carry = 1; while (carry && iter != end) { int value = (*iter - '0') + carry; carry = (value / 10); *iter = '0' + (value % 10); ++iter; } if (carry) s.insert(0, "1"); } int main() { std::string big_number = "123456789012345678901234567899"; std::cout << "before increment: " << big_number << "\n"; increment_numerical_string(big_number); std::cout << "after increment: " << big_number << "\n"; } </code></pre> <p>You can use this in a loop to increment your big number and <a href="https://stackoverflow.com/a/8362657/227755">check if the resulting string is a palindrome</a>:</p> <pre><code>if( equal(s.begin(), s.begin() + s.size()/2, s.rbegin()) ) std::cout << "is a palindrome.\n"; else std::cout << "is NOT a palindrome.\n"; </code></pre> <p><strong>Edit</strong></p> <p>I do not claim this to be an efficient and correct solution to the problem. It's just a representation and incrementing method for big numbers.</p>

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