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POUITextFieldDelegate, checking if textFields have text in it
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  1. POUITextFieldDelegate, checking if textFields have text in it
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    copied!<p>i have a little problem. There are two textFields in my TableView which set the property of an object. In order to do so i want to force the user to write something in the textField before the string is actually been set to the object. So basically a simple <code>([textField.text length] &gt; 0)</code> thing. But i want that the user have to write strings in both the two textFields to finally enable the "Done"-Button. I solved this earlier but with only one text Field with the following <code>UITextFieldDelegate</code> method.</p> <pre><code>- (BOOL)textField:(UITextField *)theTextField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string { NSString *newText = [theTextField.text stringByReplacingCharactersInRange:range withString:string]; self.doneBarButton.enabled = ([newText length] &gt; 0); return YES; } </code></pre> <p>My solution for the new problem, so now with two textFields is this one:</p> <pre><code>- (BOOL)textField:(UITextField *)theTextField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string { NSString *newText = [theTextField.text stringByReplacingCharactersInRange:range withString:string]; if ([theTextField.placeholder isEqualToString:@"textField1"]) { if ([theTextField.text length] &gt; 0) { enabledVokabel = YES; } else { enabledVokabel = NO; } } if ([theTextField.placeholder isEqualToString:@"textField2"]) { if ([theTextField.text length] &gt; 0) { enabledUebersetung = YES; } else { enabledUebersetung = NO; } } self.doneBarButton.enabled = (enabledVokabel &amp;&amp; enabledUebersetung); return YES; } </code></pre> <p>So i want the doneBarButton been enabled when both of the textFields (textField1 and textField2) are filled with text. But i want it that way that if the user has deleted the text he/she just wrote in the doneBarButton is disabled as soon as the textFields are empty. It doesn't work that way. Do you have a solution? Or maybe a better way to solve it?</p>
 

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