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POWhy can't I use std::string with libcurl?
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  1. POWhy can't I use std::string with libcurl?
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    copied!<p>I'm trying to make a very simple program that request a few pages, here is my code so far:</p> <pre><code>string fUrl = "http://google.com/"; int main(int argc, char *argv[]) { CURL *curl; CURLcode res; curl = curl_easy_init(); if (curl) { char const* chFUrl = fUrl.c_str(); //char const chFUrl[] = "http://google.com/"; curl_easy_setopt(curl, CURLOPT_URL, chFUrl); curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION, 1L); res = curl_easy_perform(curl); if (res != CURLE_OK) fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res)); curl_easy_cleanup(curl); cout &lt;&lt; chFUrl &lt;&lt; endl; system("pause"); } return 0; } </code></pre> <p>Now, notice that I'm trying to passa fUrl.c_str() to curl, but nothing happens, it simply skip through the curl functions, print the url and pause.<br> If I comment out thar line, and uncomment the "char const chFUrl[]...", everything works just fine and curl output the html response to the terminal.</p> <p>When I run through the fUrl.c_str() and it doesn't work, nothing is printed to the console on VS. I have very little experience with C++, so any ideas is appreciated.</p> <p>--Edit: I just tested this code:</p> <pre><code>char const chFUrl[] = "http://google.com"; for (int i = 0; i &lt; sizeof(chFUrl); i++) { cout &lt;&lt; chFUrl[i] &lt;&lt; endl; } </code></pre> <p>And it output the whole url to the terminal, however, when I use this:</p> <pre><code>char const* chFUrl = fUrl.c_str(); for (int i = 0; i &lt; sizeof(chFUrl); i++) { cout &lt;&lt; chFUrl[i] &lt;&lt; endl; } </code></pre> <p>It only outputs "http", even tough if I cout chFUrl[4] I get the ":".</p>
 

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