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copied!<p>You can use a custom deserializer for your use case. Here is what it will look like:</p> <pre class="lang-java prettyprint-override"><code>import java.io.IOException; import com.fasterxml.jackson.core.JsonParser; import com.fasterxml.jackson.core.JsonProcessingException; import com.fasterxml.jackson.databind.DeserializationContext; import com.fasterxml.jackson.databind.JsonDeserializer; import com.fasterxml.jackson.databind.JsonNode; public class StudyDeserializer extends JsonDeserializer<Study> { @Override public Study deserialize(JsonParser parser, DeserializationContext context) throws IOException, JsonProcessingException { JsonNode studyNode = parser.readValueAsTree(); Study study = new Study(); study.setStudyId(studyNode.get("studyId").asInt()); Patient patient = new Patient(); JsonNode patientNode = studyNode.get("patient"); patient.setPatientId(studyNode.get("patientId").asInt()); patient.setName(patientNode.get("name").asText()); patient.setLastName(patientNode.get("lastName").asText()); study.setPatient(patient); return study; } } </code></pre> <p>Specify the above class as your deserializer in the <code>Study</code> class:</p> <pre class="lang-java prettyprint-override"><code>import com.fasterxml.jackson.databind.annotation.JsonDeserialize; @JsonDeserialize(using = StudyDeserializer.class) public class Study { Integer studyId; Patient patient; // Getters and setters } </code></pre> <p>Now, the JSON input you have specified should get deserialized as expected.</p>

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