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copied!<p>When you use a pattern like </p> <pre><code>DateTimeFormat.forPattern("MMddyyyy") </code></pre> <p>it can read a date like <code>"120100"</code>. What it does is read the <code>12</code> for <code>MM</code>, the <code>01</code> for <code>dd</code>, and <a href="http://joda-time.sourceforge.net/apidocs/org/joda/time/format/DateTimeFormat.html" rel="noreferrer"><code>00</code> as a literal value for <code>yyyy</code>, ie. <code>0</code> starting at year <code>0</code>, so <code>0000</code></a>. </p> <p>Because that pattern appears before the <code>MMddyy</code> in your <code>parsers</code> array, it will be used to parse your date string.</p> <p>What you'll want to do, along with reordering or removing that format, is use a pivot year.</p> <pre><code>public static void main(String[] args) throws Exception { String str = "120100"; DateTimeParser[] formats = { DateTimeFormat.forPattern("MM/dd/yyyy").getParser(), DateTimeFormat.forPattern("MM/dd/yy").getParser(), DateTimeFormat.forPattern("MM-dd-yyyy").getParser(), DateTimeFormat.forPattern("MM-dd-yy").getParser(), DateTimeFormat.forPattern("MMddyy").getParser() }; DateTimeFormatter formatter = new DateTimeFormatterBuilder().append(null, formats).toFormatter() .withPivotYear(1950).withLocale(Locale.US); DateTime dateTime = formatter.parseDateTime(str); System.out.println(dateTime); } </code></pre> <p>prints </p> <pre><code>1900-12-01T00:00:00.000-05:00 </code></pre> <p>I'm still trying to figure out how <code>appendTwoDigitYear</code> works.</p>

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