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copied!<p>Your only providing a linkable object for the class in the translation unit, but the member function is templated on another parameter and has also to be explicitly specified.</p> <p>I don't know if there is a more elegant way, but one compilable version would be:</p> <pre><code>template bool IShader<bool>::getProperty<bool> (const std::string& propertyName, ShaderProperty<bool>** outProp); </code></pre> <p>VC8 and GCC 3.4 both allow to leave out the <code><bool></code> after the function name. I'm however not sure about the correct syntax in that case.</p> <p>But as long as you're not having problems with the compilation time in a big project, save yourself the trouble and put the method definitions (marked inline) in a header.<br> If you're just worried about the size of the header file, move the definitions in another header file, e.g. <em>IShaderImpl.h</em>, that you include at the end of <em>IShader.h</em>.</p> <p>Quick sample to remove doubts:</p> <pre><code>// IShader.h template<typename T> struct ShaderProperty {}; template <typename T> class IShader { public: template <typename U> void getProperty(ShaderProperty<U>**); }; // IShader.cpp #include <iostream> #include "IShader.h" template<typename T> template<typename U> void IShader<T>::getProperty(ShaderProperty<U>**) { std::cout << "moo" << std::endl; } template class IShader<bool>; template void IShader<bool>::getProperty(ShaderProperty<bool>**); // main.cpp #include "IShader.h" int main() { IShader<bool> b; ShaderProperty<bool>** p; b.getProperty(p); } </code></pre>

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