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POPlotting a simple 2D square with matplotlib
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copied!<p><img src="https://i.stack.imgur.com/4pvD4.jpg" alt="enter image description here">I am working n a project where I need to do the top and side views of a cube, but I don't know how to draw the square that represent the view from the top. Here is the code of the cube: </p> <pre><code>from mpl_toolkits.mplot3d import Axes3D import matplotlib.pyplot as plt import numpy as np from itertools import product, combinations, cycle from numpy import sin, cos from matplotlib.patches import Rectangle, Circle, PathPatch import mpl_toolkits.mplot3d.art3d as art3d fig = plt.figure() ax = fig.gca(projection='3d') ax.set_aspect("auto") ax.set_autoscale_on(True) #dibujar cubo r = [-1, 1] for s, e in combinations(np.array(list(product(r,r,r))), 2): if np.sum(np.abs(s-e)) == r[1]-r[0]: ax.plot3D(*zip(s,e), color="b") #dibujar punto ax.scatter([0],[0],[0],color="g",s=100) #dibujar vector from matplotlib.patches import FancyArrowPatch from mpl_toolkits.mplot3d import proj3d class Arrow3D(FancyArrowPatch): def __init__(self, xs, ys, zs, *args, **kwargs): FancyArrowPatch.__init__(self, (0,0), (0,0), *args, **kwargs) self._verts3d = xs, ys, zs def draw(self, renderer): xs3d, ys3d, zs3d = self._verts3d xs, ys, zs = proj3d.proj_transform(xs3d, ys3d, zs3d, renderer.M) self.set_positions((xs[0],ys[0]),(xs[1],ys[1])) FancyArrowPatch.draw(self, renderer) #print "ingrese coordenada inicial: " m=float(input("Ingrese valor de vector: ")) a = Arrow3D([0,0],[0,1],[0,0], mutation_scale=20, lw=1, arrowstyle="-|>", color="k") b = Arrow3D([0,-1],[0,0],[0,0], mutation_scale=20, lw=1, arrowstyle="-|>", color="r") c = Arrow3D([0,0],[0,0],[0,1], mutation_scale=20, lw=1, arrowstyle="-|>", color="b") d = Arrow3D([0,0],[0,0],[0,-1], mutation_scale=20, lw=1, arrowstyle="-|>", color="g") e = Arrow3D([0,m],[0,0],[0,0], mutation_scale=20, lw=1, arrowstyle="-|>", color="c") f = Arrow3D([0,0],[0,-0.5],[0,0], mutation_scale=20, lw=1, arrowstyle="-|>", color="m") ax.add_artist(a) ax.add_artist(b) ax.add_artist(c) ax.add_artist(d) ax.add_artist(e) ax.add_artist(f) a = [0, 0, 0] b = [m, 0, 1] orig = [0, 0, 0] for (_b, _e), _c in zip([[orig, a], [orig, b], [a, b]], cycle(['m', 'r', 'g', 'b'])): xs, ys, zs = zip(_b, _e) res = Arrow3D(xs, ys, zs, mutation_scale=20, lw=1, arrowstyle="simple", color='y') ax.add_artist(res) plt.show() </code></pre> <p>So, How can I do the top view of the cube in a subplot like the example image?</p>

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