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copied!<p>OK - Solution for my question 2 is here: I'm still working on fixing question 1.</p> <p><a href="http://scriptlerweb.appspot.com/script/show/102001" rel="nofollow noreferrer">http://scriptlerweb.appspot.com/script/show/102001</a></p> <p><strong>bulkDeleteJenkinsBuildsExceptOne_OfAGivenRelease.groovy</strong></p> <pre><code>/*** BEGIN META { "name" : "Bulk Delete Builds except the given build number", "comment" : "For a given job and a given build numnber, delete all builds of a given release version (M.m.interim) only and except the user provided one. Sometimes a Jenkins job use Build Name setter plugin and same job generates 2.75.0.1 and 2.76.0.43", "parameters" : [ 'jobName', 'releaseVersion', 'buildNumber' ], "core": "1.409", "authors" : [ { name : "Arun Sangal" } ] } END META **/ // NOTE: Uncomment parameters below if not using Scriptler >= 2.0, or if you're just pasting the script in manually. // ----- Logic in this script takes 5000 as the infinite number, decrease / increase this value from your own experience. // The name of the job. //def jobName = "some-job" // The release / version of a Jenkins job - i.e. in case you use "Build name" setter plugin in Jenkins for getting builds like 2.75.0.1, 2.75.0.2, .. , 2.75.0.15 etc. // and over the time, change the release/version value (2.75.0) to a newer value i.e. 2.75.1 or 2.76.0 and start builds of this new release/version from #1 onwards. //def releaseVersion = "2.75.0" // The range of build numbers to delete. //def buildNumber = "5" def lastBuildNumber = buildNumber.toInteger() - 1; def nextBuildNumber = buildNumber.toInteger() + 1; import jenkins.model.*; import hudson.model.Fingerprint.RangeSet; def jij = jenkins.model.Jenkins.instance.getItem(jobName); //def build = jij.getLastBuild(); println "" println("- Jenkins Job_Name: ${jobName} -- Version: ${releaseVersion} -- Keep Build Number: ${buildNumber}"); println "" println " -- Range before given build number: ${buildNumber}" println "" def setBuildRange = "1-${lastBuildNumber}" def range = RangeSet.fromString(setBuildRange, true); jij.getBuilds(range).each { if ( it.getDisplayName().find(/${releaseVersion}.*/)) { println " ## Deleting >>>>>>>>>: " + it.getDisplayName(); // Trying to find - how to NOT delete a build in Jenkins if it's marked as "keep this build forever". If someone has an idea, please update this script with a newer version in GitHub. //if ( !build.isKeepLog()) { it.delete(); //} else { // println "build -- can't be deleted as :" + build.getWhyKeepLog(); //} } } println "" println " -- Range after given build number: ${buildNumber}" println "" setBuildRange = "${nextBuildNumber}-5000" range = RangeSet.fromString(setBuildRange, true); jij.getBuilds(range).each { if ( it.getDisplayName().find(/${releaseVersion}.*/)) { println " ## Deleting >>>>>>>>>: " + it.getDisplayName(); it.delete(); } } println "" println("- Builds have been successfully deleted for the above mentioned release: ${releaseVersion}") println "" </code></pre> <p><img src="https://i.stack.imgur.com/NHvVm.jpg" alt="enter image description here"></p> <p>One can also call this script via a Jenkins job (requires 3 parameters as mentioned in the scriptler script) -OR call it from browser as well: using the following link:</p> <p>http ://YourJenkinsServerName:PORT/job/Some_Jenkins_Job_That_You_Will_Create/buildWithParameters?jobName=Test_AppSvc&releaseVersion=2.75.0&buildNumber=15</p>

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