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copied!<p>Here's a fairly simple solution in JavaScript, tested via Node. Of course, you'll need to adjust the input and output methods.</p> <pre><code>var s = "\n\ --------------------------------\n\ I I\n\ I ------- ------- I\n\ I I I I I I\n\ I I A I I B I I\n\ I I I I I I\n\ I ------- ------- I\n\ I I\n\ I I\n\ --------------------------------\n\ "; var lines = s.split('\n'); var outer_box_top_re = /--+/g; var i; for (i=0; i<lines.length; i++) { while ((res = outer_box_top_re.exec(lines[i])) != null) { L = res.index R = outer_box_top_re.lastIndex process_box(i, L, R) } } function process_box(T, L, R) { console.log('<div top="' + T + '" left="' + L + '" right="' + R + '">') blank_out(T, L, R) var i = T; while (1) { i += 1; if (i >= lines.length) { console.log('Fell off bottom of ascii-art without finding bottom of box'); process.exit(1); } var line = lines[i]; if (line[L] == 'I' && line[R-1] == 'I') { // interior // Look for (the tops of) sub-boxes. // (between L+1 and R-2) var inner_box_top_re = /--+/g; // Inner and outer need to be separate so that // inner doesn't stomp on outer's lastIndex. inner_box_top_re.lastIndex = L+1; while ((res = inner_box_top_re.exec(lines[i])) != null) { sub_L = res.index; sub_R = inner_box_top_re.lastIndex; if (sub_L > R-1) { break; } process_box(i, sub_L, sub_R); } // Look for any other content (i.e., a box label) content = lines[i].substring(L+1, R-1); if (content.search(/[^ ]/) != -1) { console.log(content); } blank_out(i, L, R); } else if (line.substring(L,R).match(/^-+$/)) { // bottom blank_out(i, L, R); break; } else { console.log("line " + i + " doesn't contain a valid continuation of the box"); process.exit(1) } } console.log('</div>') } function blank_out(i, L, R) { lines[i] = ( lines[i].substring(0,L) + lines[i].substring(L,R).replace(/./g, ' ') + lines[i].substring(R) ); } </code></pre>

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