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copied!<p>As promised the easy way: you basically send the broadcast synchroniously and if there is a receiver, you'll set a static flag in your service class, which let's the service know it's already handled:</p> <pre><code>public class TestService extends IntentService { public volatile static boolean isHandled = false; public static final String INTENT_ACTION_HANDLEGCM = "com.intentexample.gcm"; ... @Override protected void onHandleIntent(Intent intent) { ... Intent toActivityIntent = new Intent(); toActivityIntent.setAction(INTENT_ACTION_HANDLEGCM); // toActivity: put other stuff into extras, which you need to update your UI TestService.isHandled = false; LocalBroadcastManager.getInstance(this).sendBroadcastSync(toActivityIntent); if (!TestService.isHandled) { // post your notification to the notification bar } } } </code></pre> <p>and register & unregister the broadcast receiver with the intent filter for INTENT_ACTION_HANDLEGCM in your activities onResume and onPause (remember to use LocalBroadcastManager)</p> <pre><code>public class MyActivity extends Activity { BroadcastReceiver receiver = new BroadcastReceiver() { @Override public void onReceive(Context context, Intent intent) { TestService.isHandled = true; // update the UI } }; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); } @Override protected void onResume() { super.onResume(); LocalBroadcastManager.getInstance(this).registerReceiver(receiver, new IntentFilter(TestService.INTENT_ACTION_HANDLEGCM)); } @Override protected void onPause() { super.onPause(); LocalBroadcastManager.getInstance(this).unregisterReceiver(receiver); } } </code></pre> <p>NOTE: this code is untested, but should give you the general idea. I personally wouldn't do it this way except:</p> <ul> <li>under time pressure</li> <li>the feature is a minor feature and won't be extended anytime soon.</li> </ul>

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