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POPerl: Pushing a 1d array into a 3d sub-array
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copied!<p>I am trying to push/unshift a 1D array in a 2D array which is a sub-array of a 3D array. You can check a example code in <a href="http://codepad.org/5s8Og64k" rel="nofollow">http://codepad.org/5s8Og64k</a> to make this more clear, I copy it also here:</p> <pre><code>use Data::Dumper; # @arr_3d ; $arr_3d[0][0][0] = 1; $arr_3d[0][1][0] = 2; $arr_3d[0][0][1] = 4; $arr_3d[0][1][1] = 3; # @arr_1d ; $arr_1d[1] = "new1"; $arr_1d[0] = "new0"; print Dumper(\@arr_3d); unshift @{$arr_3d[0]},\@arr_1d; print Dumper(\@arr_3d); </code></pre> <p>In other words, if we define the 3D array's dimensions x-y-z and consider x constant then we get a "2D" array . I want to push a 1D array into this 2D "sub-array" of the original 3D array.</p> <p>The example code actually does that, <strong>BUT</strong> when I try applying it to my main script, the dumper dumps "<strong>$VAR1->[0][0]</strong>" in the place of all the previously pushed-in data, and only dumps the data from the last pushed-in 1D array.</p> <p>Any idea what is could be causing that or of a more effective way to do the push I describe?</p> <p><em>Extra info:</em> The actual data structure is created within a loop, something like:</p> <pre><code>unshift @{$arr_3d[$index]},\@arr_1d; print @arr_1d; # This prints successfully the 1D array </code></pre> <p>where "@arr_1d" is created be simply assigning individual elements:</p> <pre><code>$arr_1d[0]='a'; $arr_1d[1]='b'; # etc, etc.. </code></pre> <p>Thanks for your time, Giorgos</p>

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