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PODeleting a row from dynamic table when click on image
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  1. PODeleting a row from dynamic table when click on image
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    copied!<p>I am working on a PHP/MySQL grid that list two little icons, one is expected to delete the actual register and remove the row and the other is supposed to redirect the user to another page opening the details of the selected register. This is how my code looks like:</p> <p>PHP:</p> <pre><code>$output .='&lt;tr id="'.$id.'"&gt;'; $output .='&lt;td align="center"&gt;'.$expiration_date.'&lt;/td&gt;'; $output .='&lt;td&gt;'.$title.'&lt;/td&gt;'; $output .='&lt;td&gt;'.$title_pt.'&lt;/td&gt;'; $output .='&lt;td align="center"&gt;'.$last_update.'&lt;/td&gt;'; $output .='&lt;td align="center"&gt;'.$active_pack.'&lt;/td&gt;'; $output .='&lt;td align="center" class="icon_grid"&gt;&lt;a id="edit" title="Open the register." href="special_pack_open.php?id='.$id.'"&gt;&lt;img src="images/Write2.gif" width="16" height="16" /&gt;&lt;/a&gt;&lt;/td&gt;'; $output .='&lt;td align="center" class="icon_grid"&gt;&lt;a id="delete" title="Delete the register." href="#"&gt;&lt;img src="images/Trash.gif" width="16" height="16" /&gt;&lt;/a&gt;&lt;/td&gt;'; $output .='&lt;/tr&gt;'; </code></pre> <p>JQuery:</p> <pre><code>&lt;script type="text/javascript"&gt; $(document).ready(function() { $('table tr[id]').click(function(){ $(this).closest("tr").remove(); var obj = $(this); $.ajax({ type: "POST", url: 'delete_package.php', data: { pk_id: obj.attr("id")}, dataType: "json", success: function(data, evt) { if (data.success == "true") { alert('The record has been deleted successfuly!'); } else { alert('error'); } } }) }) }) &lt;/script&gt; </code></pre> <p>Everything is working very good. When I click in the Trash.gif, it deletes the register and remove the row. The thing is when I click on the Write2.Gif (second link) where it is supposed to go to the next page, it does the same action as delete does! How can I change my JQuery code to make it understand that only one link is dedicated to delete the register?</p> <p>Thank you.</p>
 

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