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PODrawing Euler Angles rotational model on a 2d image
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copied!<p>I'm currently attempting to draw a 3d representation of euler angles within a 2d image (no opengl or 3d graphic windows). The image output can be similar to as below.</p> <p><img src="https://i.stack.imgur.com/uaT1k.png" alt="euler angles"></p> <p>Essentially I am looking for research or an algorithm which can take a Rotation Matrix or a set of Euler angles and then output them onto a 2d image, like above. This will be implemented in a C++ application that uses OpenCV. It will be used to output annotation information on a OpenCV window based on the state of the object.</p> <p>I think I'm over thinking this because I should be able to decompose the unit vectors from a rotation matrix and then extract their x,y components and draw a line in cartesian space from (0,0). Am i correct in this thinking?</p> <p>EDIT: I'm looking for an Orthographic Projection. You can assume the image above has the correct camera/viewing angle.</p> <p>Any help would be appreciated.</p> <p>Thanks,</p> <p>EDIT: The example source code can now be found in my repo. Header: <a href="https://bitbucket.org/jluzwick/tennisspindetector/src/6261524425e8d80772a58fdda76921edb53b4d18/include/projection_matrix.h?at=master" rel="nofollow noreferrer">https://bitbucket.org/jluzwick/tennisspindetector/src/6261524425e8d80772a58fdda76921edb53b4d18/include/projection_matrix.h?at=master</a></p> <p>Class Definitions: <a href="https://bitbucket.org/jluzwick/tennisspindetector/src/6261524425e8d80772a58fdda76921edb53b4d18/src/projection_matrix.cpp?at=master" rel="nofollow noreferrer">https://bitbucket.org/jluzwick/tennisspindetector/src/6261524425e8d80772a58fdda76921edb53b4d18/src/projection_matrix.cpp?at=master</a></p> <p>It's not the best code but it works and shows the steps necessary to get the projection matrix described in the accepted answer.</p> <p>Also here is a youtube vid of the projection matrix in action (along with scale and translation added): <a href="http://www.youtube.com/watch?v=mSgTFBFb_68" rel="nofollow noreferrer">http://www.youtube.com/watch?v=mSgTFBFb_68</a></p>

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