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copied!<p>I would suggest that for each collection of squares that are logically joined together you create an instance of something like:</p> <pre><code>private class TileRef { public Tile tile; public int X,Y,Width,Height;} </code></pre> <p>Then have either a 2-dimensional or jagged array of TileRef. All of the squares in a joined-together group should hold a reference to the same <code>TileRef</code> object. That should allow you to very quickly find the <code>TileRef</code> associated with any square on the board without need for conditional logic to deal with different-sized tiles.</p> <p>To construct a grid of size-one tiles:</p> <pre><code>TileRef[,] tiles; TileMapper(int xsize, int ysize) { tiles = new TileRef[xsize,ysize]; for (int x=0; x < xsize; x++) for (int y=0; y < xsize; y++) { var thisRef = new TileRef(); thisRef.X = x; thisRef.Y = y; thisRef.Width = 1; thisRef.Height = 1; thisRef.Tile = new Tile(); // Make a default tile instance somehow tiles[x][y] = thisRef; } } To join a bunch of squares together into a blob: public JoinSquares(int x, int y, int width, int height) { var thisRef = new TileRef(); thisRef.X = x; thisRef.Y = y; thisRef.Width = 1; thisRef.Height = 1; thisRef.Tile = new Tile(); // Make a default tile instance somehow for (i=0; i<width; i++) for (j=0; j<height; j++) tiles[x+i,y+j] = thisRef; } public SeparateSquares(int x, int y) { var oldRef = tiles[x,y]; x=oldref.X; y=oldref.Y; var width=oldref.Width; var height=oldref.Height; for (i=0; i<width; i++) for (j=0; j<height; j++) { var thisRef = new TileRef(); thisRef.X = x+i; thisRef.Y = y+j; thisRef.Width = 1; thisRef.Height = 1; thisRef.Tile = new Tile(); // Make a default tile instance somehow tiles[x+i,y+j] = thisRef; } } To change the `Tile` associated with a "blob", simply public Tile this[int x, int y] { get { return tiles[x,y].Tile; } set { tiles[x,y].Tile = value; } } </code></pre> <p>Loops are required to join squares together or separate them, but not to simply change the attributes associated with a blob by changing its <code>Tile</code> property.</p>

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