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copied!<p>As watcher said, PHP does not do variable interpolation within single-quoted strings.</p> <blockquote> <p>The most important feature of double-quoted strings is the fact that variable names will be expanded.</p> </blockquote> <p><a href="http://ca.php.net/manual/en/language.types.string.php" rel="nofollow">Read more about strings from the PHP manual.</a></p> <p>Therefore, when you view the HTML, you will <em>literally</em> see this:</p> <pre><code><img src="$image" height="50" width="50" /> </code></pre> <p>Your code should be:</p> <pre><code>while($result = mysql_fetch_array($resul,MYSQL_ASSOC)) { $image = $result['image']; echo $result['company'] . " " . $result['model'] . "<br>"; echo "<img src='$image' height='50' width='50'>"; } </code></pre> <p>Alternatively, interpolate the array value:</p> <pre><code>while($result = mysql_fetch_array($resul,MYSQL_ASSOC)) { echo $result['company'] . " " . $result['model'] . "<br>"; echo "<img src='{$result['image']}' height='50' width='50'>"; } </code></pre> <p>If the filename contains spaces or other special characters, you may need to use <a href="http://ca.php.net/manual/en/function.rawurlencode.php" rel="nofollow"><code>rawurlencode()</code></a>. In this case, you <strong>must</strong> concatenate the string since you are calling a function that returns a <code>string</code> value:</p> <pre><code>echo "<img src='" . rawurlencode($result['image']) . "' height='50' width='50'>"; </code></pre>

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