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PO$1 of [...] has no declared type
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copied!<p>I am unfamiliar with Yacc and trying to get an example I found <a href="http://pic.dhe.ibm.com/infocenter/aix/v6r1/index.jsp?topic=%2Fcom.ibm.aix.genprogc%2Fdoc%2Fgenprogc%2Fie_prog_4lex_yacc.htm" rel="nofollow">here</a> to work. When I try to compile with <code>yacc -d calc.yacc</code>, I get the following errors.</p> <blockquote> <p>calc.yacc:42.17-18: $1 of `stat' has no declared type</p> <p>calc.yacc:96.22-23: $1 of `expr' has no declared type</p> <p>calc.yacc:105.17-18: $1 of `number' has no declared type</p> <p>calc.yacc:106.20-21: $1 of `number' has no declared type</p> <p>calc.yacc:110.29-30: $2 of `number' has no declared type</p> </blockquote> <p>I tried googling and from what I can tell, the solution has to do with %type, but I'm not sure what to add.</p> <p>The code is below:</p> <pre><code>%{ #include <stdio.h> int regs[26]; int base; %} %start list %union { int a; } %type <a> expr number %token DIGIT LETTER %left '|' %left '&' %left '+' '-' %left '*' '/' '%' %left UMINUS /*supplies precedence for unary minus */ %% /* beginning of rules section */ list: /*empty */ | list stat '\n' | list error '\n' { yyerrok; } ; stat: expr { printf("%d\n",$1); } | LETTER '=' expr { regs[$1] = $3; } ; expr: '(' expr ')' { $$ = $2; } | expr '*' expr { $$ = $1 * $3; } | expr '/' expr { $$ = $1 / $3; } | expr '%' expr { $$ = $1 % $3; } | expr '+' expr { $$ = $1 + $3; } | expr '-' expr { $$ = $1 - $3; } | expr '&' expr { $$ = $1 & $3; } | expr '|' expr { $$ = $1 | $3; } | '-' expr %prec UMINUS { $$ = -$2; } | LETTER { $$ = regs[$1]; } | number ; number: DIGIT { $$ = $1; base = ($1==0) ? 8 : 10; } | number DIGIT { $$ = base * $1 + $2; } ; %% main() { return(yyparse()); } yyerror(s) char *s; { fprintf(stderr, "%s\n",s); } yywrap() { return(1); } </code></pre>

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