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copied!<p>Given this declaration:</p> <pre><code>int (*Arr)[8]; </code></pre> <p>you can assign it the address of an <code>int</code> array of size 8:</p> <pre><code>int data[8]; Arr = &data; </code></pre> <p>You can modify <code>data</code> through <code>Arr</code>:</p> <pre><code>(*Arr)[i] = value; </code></pre> <p>Note the parentheses around <code>*Arr</code>. They're needed to dereference <code>Arr</code> <em>before</em> applying the index to it, since the index <code>[]</code> operator has a higher precedence.</p> <p>An important thing to understand here is that <code>data</code> is not dynamically allocated. If you keep its address around after it has gone out of scope, you'll get a dangling pointer (a pointer that points to something that no longer exists.)</p> <p>To dynamically allocate an array and assign it to <code>Arr</code>, you can use a typecast on the result of <code>new</code> as follows:</p> <pre><code>int (*Arr)[8] = reinterpret_cast<int(*)[8]>(new int[8]); </code></pre> <p>(A working example can be found on <a href="http://ideone.com/VWYxsE" rel="nofollow">ideone</a>.)</p> <p>Of course it doesn't make much sense to do this in such a roundabout way, as you can instead just:</p> <pre><code>int* Arr = new int[8]; </code></pre> <p>And of course you can use an <a href="http://www.cplusplus.com/reference/vector/vector" rel="nofollow">std::vector</a> instead and avoid manual memory management completely:</p> <pre><code>std::vector<int> Arr; </code></pre> <p>Which provides you with an array that grows on its own as needed.</p>

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