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copied!<pre><code>else if (x <= b.length && y <= b[x].length && x <= a.length && y <= a[x].length) { merged[x][y] = ((a[x][y] + b[x][y]) /2); // <= problematic line } </code></pre> <p>in this line you try to reach a point where it's out of a's bound. In my example, i set a to be <code>(10, 10)</code> and b to be <code>(5, 20)</code>. It crashed when <code>x = 0, y = 10</code>. Now, as you can see <code>a[0][10]</code> is out of bounds. </p> <p>Here is my trial code and it's output:</p> <pre><code>else if (x <= b.length && y <= b[x].length && x <= a.length && y <= a[x].length) { System.out.println("x = " + x + " y = " + y); System.out.println("merged.length = " + merged.length); System.out.println("merged[0].length = " + merged[0].length); System.out.println("a.length = " + a.length); System.out.println("a[0].length = " + a[0].length); System.out.println("b.length = " + b.length); System.out.println("b[0].length = " + b[0].length); System.out.println(); System.out.println(); merged[x][y] = ((a[x][y] + b[x][y]) /2); } </code></pre> <p>Output:</p> <pre><code>x = 0 y = 10 merged.length = 10 merged[0].length = 20 a.length = 10 a[0].length = 10 b.length = 5 b[0].length = 20 </code></pre> <p>EDIT: Just noticed solution I proposed is not applicable for you.</p> <p>EDIT2: <code>x <= a.length</code> and <code>y <= a[x].length</code> kind of statements needs to be changed into <code>x < a.length</code> and <code>y < a[x].length</code> or <code>x <= a.length - 1</code> and <code>y <= a[x].length - 1</code></p>

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