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POUsing round() to get exact value - PHP
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copied!<p>Hey guy's I am working on a project of mine which involves the use of money. I am trying to not use round anymore because, it's rounding things to nearest tenth and I need exact numbers. One reason I was using it, was because it was giving a whole number.</p> <p>The way I am working my number system is that <code>100 = $1, 2000 = $20, etc..</code> I was currently using the round function because it would get rid of the decimal point for me and give me a whole number, lets say: <code>223</code> which in turn would = <code>$2.23</code>.</p> <p>Here is what I am using: </p> <pre><code>$amount += round(($amount / 29) + 30); </code></pre> <p>Here are the numbers:</p> <p>Lets say we have a charge of <code>100 and we add 125 which equal 225 (USD $2.25)</code>. Now we add taxes and processing: <code>+ 2.9% + $.30</code>. After multiplying <code>2.25 by 2.9%</code> and adding <code>.30</code> the amount would be: <code>0.36525</code> - this is the amount that should be added than to the <code>$2.25 which than would be 261 = $2.61</code></p> <p>The issue is because of the rounding, when I look in my Stripe panel <code>(I am using Stripe API for payments)</code> I see a charge of <code>$2.63</code>. So my question is, how would I go about making it exact without having any rounding and decimal places.</p> <p>UPDATE:</p> <p>Here is the above example more explained: </p> <p>Lets say we have a charge of <code>100 and we add 125 which equal 225 (USD $2.25)</code>. Now we add taxes and processing: <code>+ 2.9% + $.30</code>. After multiplying <code>2.25 by 2.9%</code> and adding <code>.30</code> the amount would be: <code>0.36525</code> - this is the amount that should be added than to the <code>$2.25 which than would be 261 = $2.61</code></p> <p>So now with that the actual value of amount that should be charged is <code>$2.61</code> but instead when using the round it gives me <code>263</code> which also means <code>$2.63</code>. The above example is the simple math that is correct.</p>

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