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PObinary list contains all possible options by knowing its length in python
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copied!<p>i am trying to get a binary list contains all possibilities by providing the length of these possible lists , now i found a solution but it is not very handy to be used in other functions.</p> <p>example : i want a list of lists each one represents one binary option of four digits. </p> <p>if the length is 4 then the result should be the following.</p> <pre><code>[[0, 0, 0, 0], [0, 0, 0, 1], [0, 0, 1, 0], [0, 0, 1, 1], [0, 1, 0, 0], [0, 1, 0, 1], [0, 1, 1, 0], [0, 1, 1, 1], [1, 0, 0, 0], [1, 0, 0, 1], [1, 0, 1, 0], [1, 0, 1, 1], [1, 1, 0, 0], [1, 1, 0, 1], [1, 1, 1, 0], [1, 1, 1, 1]] </code></pre> <p>what i have done is by the following code: </p> <pre><code>>>> [[a, b, c, d] for a in [0,1] for b in [0,1] for c in [0,1] for d in [0,1]] </code></pre> <p>Now , i am looking for a way that by knowing the length of each member binary list we can generate the big list without the need to type manually [ a, b, c, d] , so if is possible to generate the list by a function lets say L_set(4) we get the list above . and if we type L_set(3) we get the following: </p> <pre><code>[[0, 0, 0], [0, 0, 1], [0, 1, 0], [0, 1, 1], [1, 0, 0], [1, 0, 1], [1, 1, 0], [1, 1, 1]] </code></pre> <p>and by typing L_set(2) we get : </p> <pre><code>[[0, 0], [0, 1], [1, 0], [1, 1]] </code></pre> <p>and so on. </p> <p>After spending few hours i felt stuck here in this point , i hope that some of you can help. </p> <p>Thanks </p>

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