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copied!<p>comparing the hard coded javascript to ones that don't work, I notice that you are not including the double-quotes around the <code><?php $article["img"]; ?></code> snippet. The hard coded one shows</p> <pre><code>= 'url("img/gym-01.jpg")' </code></pre> <p>but the ones with the php snippet will produce</p> <pre><code> = 'url(img/gym-01.jpg)' </code></pre> <p>so perhaps if you modify it to</p> <pre><code>document.getElementById('news-img-1').style.backgroundImage = 'url("'<?php $article["img"]; ?>'")'; </code></pre> <p>OR</p> <p>edit the <code>get_news_feed</code> function as follows:</p> <p>replace these lines</p> <pre><code>$output .= '<div id="news-img-1">'; $output .= "</div>"; </code></pre> <p>with</p> <pre><code>$output .= '<div class="news-img"><img src="' . $article["img"] . '"></div>' ; </code></pre> <p>and change your css like so:</p> <pre><code>article.img-wrapper { position: relative; } div.news-img { position: absolute; top: 0; z-index: -1000; } </code></pre> <p>OR</p> <p>Modify your get_news_feed function, change the statement for the <code><div id="news-img-1"></code> output to include a data-url attribute like:</p> <pre><code>$output .= '<div class="news-img" data-url="' . $article["img"] . '">'; </code></pre> <p>Then add a jquery statement like:</p> <pre><code>$(".news-img").each( function() { $(this).css("background-image", "url(" + $(this).data("url") +")" ); }); </code></pre> <p>The jquery statement goes in a static js file as opposed to generating the script in php.</p>

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