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copied!<p>Butterchicken's solution is ok, but will only work on english versions of Windows.</p> <p>A somewhat better (language independent) solution would be to match the pattern for MAC addresses. Here I also make sure that this address has an associated IP (e.g. to filter out bluetooth devices):</p> <pre><code>public String obtainMacAddress() throws Exception { Process aProc = Runtime.getRuntime().exec("ipconfig /all"); InputStream procOut = new DataInputStream(aProc.getInputStream()); BufferedReader br = new BufferedReader(new InputStreamReader(procOut)); String aMacAddress = "((\\p{XDigit}\\p{XDigit}-){5}\\p{XDigit}\\p{XDigit})"; Pattern aPatternMac = Pattern.compile(aMacAddress); String aIpAddress = ".*IP.*: (([0-9]*\\.){3}[0-9]).*$"; Pattern aPatternIp = Pattern.compile(aIpAddress); String aNewAdaptor = "[A-Z].*$"; Pattern aPatternNewAdaptor = Pattern.compile(aNewAdaptor); // locate first MAC address that has IP address boolean zFoundMac = false; boolean zFoundIp = false; String foundMac = null; String theGoodMac = null; String strLine; while (((strLine = br.readLine()) != null) && !(zFoundIp && zFoundMac)) { Matcher aMatcherNewAdaptor = aPatternNewAdaptor.matcher(strLine); if (aMatcherNewAdaptor.matches()) { zFoundMac = zFoundIp = false; } Matcher aMatcherMac = aPatternMac.matcher(strLine); if (aMatcherMac.find()) { foundMac = aMatcherMac.group(0); zFoundMac = true; } Matcher aMatcherIp = aPatternIp.matcher(strLine); if (aMatcherIp.matches()) { zFoundIp = true; if(zFoundMac && (theGoodMac == null)) theGoodMac = foundMac; } } aProc.destroy(); aProc.waitFor(); return theGoodMac; } </code></pre>

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