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copied!<p>If you don't mind that you'll get a straight line "curve", then you only need six variables for any amount of data. Here's the source code that's going into my upcoming book; I'm sure that you can figure out how the DataPoint class works:</p> <p>Interpolation.h:</p> <pre><code>#ifndef __INTERPOLATION_H #define __INTERPOLATION_H #include "DataPoint.h" class Interpolation { private: int m_count; double m_sumX; double m_sumXX; /* sum of X*X */ double m_sumXY; /* sum of X*Y */ double m_sumY; double m_sumYY; /* sum of Y*Y */ public: Interpolation(); void addData(const DataPoint& dp); double slope() const; double intercept() const; double interpolate(double x) const; double correlate() const; }; #endif // __INTERPOLATION_H </code></pre> <p>Interpolation.cpp:</p> <pre><code>#include <cmath> #include "Interpolation.h" Interpolation::Interpolation() { m_count = 0; m_sumX = 0.0; m_sumXX = 0.0; m_sumXY = 0.0; m_sumY = 0.0; m_sumYY = 0.0; } void Interpolation::addData(const DataPoint& dp) { m_count++; m_sumX += dp.getX(); m_sumXX += dp.getX() * dp.getX(); m_sumXY += dp.getX() * dp.getY(); m_sumY += dp.getY(); m_sumYY += dp.getY() * dp.getY(); } double Interpolation::slope() const { return (m_sumXY - (m_sumX * m_sumY / m_count)) / (m_sumXX - (m_sumX * m_sumX / m_count)); } double Interpolation::intercept() const { return (m_sumY / m_count) - slope() * (m_sumX / m_count); } double Interpolation::interpolate(double X) const { return intercept() + slope() * X; } double Interpolation::correlate() const { return m_sumXY / sqrt(m_sumXX * m_sumYY); } </code></pre>

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