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copied!<p>I have this 'ere code:</p> <pre><code>#include <stdio.h> #include <stdlib.h> #include <string.h> // Library stuff typedef struct { int x, y; } _TYPE_position; typedef struct { char image[32]; _TYPE_position position; } _TYPE_object; _TYPE_object *object; int createObject(const _TYPE_object *insertionObject); int createObject(const _TYPE_object *insertionObject) { int index; _TYPE_object *newObjectPtr = realloc(object, sizeof(*object) + sizeof(_TYPE_object)); if(newObjectPtr != NULL) { object = newObjectPtr; index = sizeof(*object) / sizeof(_TYPE_object) - 1; strcpy(object[index].image, insertionObject->image); object[index].position = insertionObject->position; } else { index =- 1; } return index; } // Demo program int main(void) { _TYPE_object smile = { "smile.png", { 112, 80 } }; int smileIndex = createObject(&smile); if(smileIndex == -1) { printf("Error allocating memory for smile object"); while(1); } smile.position.x = 55; // Does nothing since the object does not point here for some reason int i; for(i = 0; i < sizeof(*object) / sizeof(_TYPE_object); i++) { printf("Create %s at { %d, %d }\n", object[i].image, object[i].position.x, object[i].position.y); } return 0; } </code></pre> <p>And it kind of works. It seems that object is not pointing to a _TYPE_object but is instead creating an exact copy of it.</p> <p>Is there a way to make the object array point to objects, rather than just recreating them. So in the above example have smile.position.x = 55; actually change the value that gets printed.</p>

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