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POOrder results of CLGeoCoder geocodeAddressString by nearest location
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  1. POOrder results of CLGeoCoder geocodeAddressString by nearest location
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    copied!<p>I'm sure that I can figure this out based on code that I have implemented in PHP in the past, but I was hoping that someone has either done this and can provide an example or knows of a way to use the iOS SDK to accomplish it.</p> <p>Here's my relevant code:</p> <pre><code>CLGeocoder *geocoder = [[CLGeocoder alloc] init]; CLLocationDistance dist = _searchDistance; CLLocationCoordinate2D point = self.locationManager.location.coordinate; CLRegion *region = [[CLRegion alloc] initCircularRegionWithCenter:point radius:dist identifier:@"Hint Region"]; [geocoder geocodeAddressString:address inRegion:region completionHandler:^(NSArray *placemarks, NSError *error) { if( error ) { // Push errors to the user } else { NSLog( [NSString stringWithFormat:@"Got results: %@", placemarks] ); } }]; </code></pre> <p>This pushes to the log something like the following:</p> <pre><code>( "300 Oak St, Phoenix, OR 97535-5722, United States @ &lt;+42.26953820,-122.81554259&gt; +/- 100.00m, region (identifier &lt;+42.26953820,-122.81554106&gt; radius 27.00) &lt;+42.26953820,-122.81554106&gt; radius 27.00m", "300 Oak St, Ashland, OR 97520, United States @ &lt;+42.19955633,-122.71289484&gt; +/- 100.00m, region (identifier &lt;+42.19955633,-122.71289484&gt; radius 138.42) &lt;+42.19955633,-122.71289484&gt; radius 138.42m", "300 Oak St, Jacksonville, OR 97530, United States @ &lt;+42.31236366,-122.97179130&gt; +/- 100.00m, region (identifier &lt;+42.31236366,-122.97179130&gt; radius 138.33) &lt;+42.31236366,-122.97179130&gt; radius 138.33m", "300 Oak St, Central Point, OR 97502, United States @ &lt;+42.37422514,-122.91427182&gt; +/- 100.00m, region (identifier &lt;+42.37422514,-122.91427182&gt; radius 138.29) &lt;+42.37422514,-122.91427182&gt; radius 138.29m", "300 Oak St, Rogue River, OR 97537, United States @ &lt;+42.43621216,-123.16864522&gt; +/- 100.00m, region (identifier &lt;+42.43621216,-123.16864522&gt; radius 138.24) &lt;+42.43621216,-123.16864522&gt; radius 138.24m" ) </code></pre> <p>In this case, the second result is the closest to my current location. I would like to have this list ordered by matches that are closest to my current location. I'm reasonably confident that I know how to do the math to figure out which location is closest, but I was hoping for a shortcut. Iterating through this array and sorting the results is going to be somewhat heavy, so I'd like to avoid that if possible.</p> <p><strong>EDIT (complete answer):</strong></p> <p>@Akash gave me the bit of information I was seeking, so I marked that answer as the correct one. If anyone is interested in sorting the results (rather than just getting the closest location), I put the unsorted results into an <code>NSDictionary</code> using the distance as a key, then used <code>compare</code> to sort the keys and then put the original <code>placemark</code> array elements into an output array ordered by the key to which they were associated in the <code>NSDictionary</code>. Here's the complete code (and the complete answer to my question):</p> <pre><code>-(NSMutableArray *)distanceSortPlacemarks:(NSArray *)inputArray fromLocation:(CLLocation *)originLocation { NSMutableArray *returnValue = [[NSMutableArray alloc] initWithCapacity:[inputArray count]]; NSMutableDictionary *sortDictionary = [[NSMutableDictionary alloc] initWithCapacity:[inputArray count]]; for( int i = 0; i &lt; [inputArray count]; i++ ) { CLPlacemark *currentPlacemark = [inputArray objectAtIndex:i]; [sortDictionary setObject:currentPlacemark forKey:[NSNumber numberWithDouble:[currentPlacemark.location distanceFromLocation:originLocation]] ]; } NSArray *sortedKeys = [[sortDictionary allKeys] sortedArrayUsingSelector:@selector(compare:)]; for( int i = 0; i &lt; [sortedKeys count]; i++ ) { CLPlacemark *currentPlacemark = [sortDictionary objectForKey:[sortedKeys objectAtIndex:i]]; [returnValue insertObject:currentPlacemark atIndex:i]; } return returnValue; } </code></pre> <p>I know this could be a little tighter (some of the variables aren't absolutely necessary), but I tend to err on the side of making code easier to understand at quick glance.</p>
 

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