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POpython/scons help: maintaining lists of source files + object files
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copied!<p>I know next to nothing about Python and I'm using scons. (if you're reading this and know Python but not scons, you can probably help me!)</p> <p>Could someone help me out and explain how I could have a variable that contains two lists? I'm not sure of the syntax. Is this right?</p> <pre><code>buildinfo = // how do you initialize a variable that has fields? buildinfo.objectFiles = []; // list of the object files buildinfo.sourceFiles = []; // list of the source files </code></pre> <p>If I have a function f() that returns a variable of this structure, what's the shortest way to append f()'s return value onto both lists? (Really f() is Sconscript() but never mind.)</p> <pre><code>// call f() several times and append the results onto buildinfo buildinfo_sub = f(...); buildinfo.objectFiles.append(buildinfo_sub.objectFiles); buildinfo.sourceFiles.append(buildinfo_sub.sourceFiles); buildinfo_sub = f(...); buildinfo.objectFiles.append(buildinfo_sub.objectFiles); buildinfo.sourceFiles.append(buildinfo_sub.sourceFiles); buildinfo_sub = f(...); buildinfo.objectFiles.append(buildinfo_sub.objectFiles); buildinfo.sourceFiles.append(buildinfo_sub.sourceFiles); </code></pre> <p>Is there a shorter way? this isn't too long but it's long enough to be error-prone.</p> <p><strong>edit</strong>: or better yet, I want to define a simple class that has two fields, objectFiles and sourceFiles, and if I call</p> <pre><code>object1.append(object2) </code></pre> <p>then object1 will append object2's objectFiles and sourceFiles fields onto its own, so I could just do:</p> <pre><code>buildinfo = BuildInfo([],[]); buildinfo.append(f(...)); buildinfo.append(f(...)); buildinfo.append(f(...)); </code></pre>

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