StackOverflow2013

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copied!<ol> <li><p>Partitioning does not need to be based solely on a unique key. However if unique key is present, then it should be included in columns used to partition the table on. To partition table on UNIXTIME column do:</p> <pre><code>ALTER TABLE MyTable PARTITION BY RANGE COLUMNS (UNIX_TIMESTAMP(datetime_column)) ( PARTITION p01 VALUES LESS THAN (2), PARTITION p02 VALUES LESS THAN (3), PARTITION p03 VALUES LESS THAN (4), PARTITION p04 VALUES LESS THAN (MAXVALUE)); </code></pre> <p>Or you can partition on datetime column stright away in MySQL 5.5+ :</p> <pre><code>ALTER TABLE MyTable PARTITION BY RANGE COLUMNS (datetime_column) ( PARTITION p01 VALUES LESS THAN ('2013-01-01'), PARTITION p02 VALUES LESS THAN ('2013-02-01'), PARTITION p03 VALUES LESS THAN ('2013-03-01'), PARTITION p04 VALUES LESS THAN (MAXVALUE)); </code></pre></li> <li><p>Fully automated version (it would keep every month in its own partition, 5 months of data held):</p> <pre><code>ALTER TABLE MyTable PARTITION BY RANGE COLUMNS (YEAR(datetime_column)*100 + MONTH(datetime_column)) ( PARTITION p201301 VALUES LESS THAN (201301), PARTITION p201302 VALUES LESS THAN (201302), PARTITION p201303 VALUES LESS THAN (201303), PARTITION p201304 VALUES LESS THAN (201304), PARTITION p201305 VALUES LESS THAN (201305), PARTITION p_MAXVALUE VALUES LESS THAN (MAXVALUE)); DECLARE @Min_Part int DECLARE @Last_Part int DECLARE @SQL varchar (1000) If (select count (distinct MONTH(datetime_column)) from MyTable) > 5 THEN BEGIN select @Min_Part = (select min(year(datetime_column)*100 + month(datetime_column)) from MyTable), @Last_Part = (select max(year(datetime_column)*100 + month(datetime_column)) from MyTable) set @SQL = 'Alter table MyTable REORGANIZE PARTITION p_MAXVALUE (into partition p' +TO_CHAR (@Last_Part) + 'values less than (' + TO_CHAR (@Last_Part) + ')' call common_schema.eval (@sql) set @SQL = 'Alter table MyTable DROP PARTITION p' + TO_CHAR (@Min_Part) call common_schema.eval (@sql) END </code></pre></li> </ol> <p>P.S. Apologies if SQL is not exactly correct - cannot parse it right now.</p>

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